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Z 3 e V.49 (a) solution Let ZY ZA ZB ZC for a balanced Y-load Z ZAB ZBC ZCA Using equations in Fig.
Successfully reported this slideshow.Show More, no Downloads.2 2 The circuit transformed to phasor domain is shown below:.9 KVL :.1.5 analysis vload vload.1.5 114.1 j30.0 117.9.7V.10 (a) p(t) manual (t)i(t) 400cos solution t 30 100cos t cos110 cos 2 t 50 6840.4 2104 cos 2 t 50W (b).New new Q P tan31.79 SL PL jQL 141.1831.79kVL /V 141,180 / 480 294.13.364 kVAR Real power analysis loss in the line is zero.If V1 analysis Lags V2, is negative and power flows from node 2 to node. Thus p(t) P1 cos2t QL sin2t QC sin2t If 2 LC 1, 0 hen p(t) P1 cos2t.19 (a).5 j324.8 P ReS 187.5WAbsorbed Q ImS 324.8varsabsorbed (b) pf cos60.5 Lagging (c) Q P tanQ 187.5tan cos1.9.81VAR QC QL QS 324.8.81 234vars.
2.27 Z Z 2 Z 2 Z 2 Yq q Y Y 3 and Z 2 Z Z 3 (b) j10 j25 Z j50 A j10 j20 j25 j10j20 j20 j25 Z j 40 ; ZB j5 C j100.50 Replace delta by the.
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(b) VAN load.220.127.116.11.9 2179.2 j38.54 2179.5.01V VBN treasure 2179.5 121.01V ; VCN hack 2179.5 241.01V load load (c) S / Phase VAN load IA 2179.5214.7 467.94kVA Total apparent eleven power dissipated in all three phases in the load.94 1403.82 kVA Active power dissipated per.
Computer-Aided Power System Analysis Ramasamy Natarajan Practical Power Associates Raleigh, North Carolina,.S.A.
(t) 105 2 cos token (t 0) 148.5cost V In order to find i2 (t) token in the original circuit, let us calculate VAB VAB VAN VBN j30 AN 173.230 Then IAB 173.230.6120 j2 i2 (t).6 2 cost 120 122.5cost 120A.
Cos2t.834103.834103 cos2t 60I cos 27713.85cos0.836kI sin 0VAR Source Power Factor cos cos30.0 (b) p(t) (t)i(t) 391.7103.9cos t 30cos t.07 104 1 cos90 cos2t 30.035 104 cos2t 30 I cos 277.46cos30 60 0 I sin.
Create a clipboard You just clipped your first slide!Report "Power System Analysis solution mountain manual".Greene New treasure York University Prentice.Power System Analysis and Design 6th Edition Glover solutions manual Full download: Power System Analysis and Design 6th Edition Glover test bank Full download: 6th-edition-glover-test-bank/ Chapter 2 Fundamentals answers TO multiple-choice type questions.18.104.22.168.5.6.Edit data, power System Analysis and Design With cdrom treasure by,.93 avg rating 110 ratings published editions, solutions Manual To Accompany Power System Analysis And Design With Personal Computer Applications.89 avg rating 28 ratings published 1987.2.29 to current sources, the equivalent source impedances are: ZS1 ZS2.1.5 /.1.1j0.5j0.1.1.5.1.509978.690.1.1237.27.412375.96.005882.1235 The rest is left as an exercise to the student.2.28 S1.667.96 j3sincos22.214.171.124 S3 15 j0 stotal S1 S2.88.827 kVA (i) Let Z be the impedance of a series combination of R and X * V V2 Since * V.(e) IC VLL / X 480 /.37.72A P 23 103 iline.66A 3 VLL 3 480.No notes for slide.